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Construction And Maintenance Of Masonry Houses by Blondet M.

By Blondet M.

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Example text

14c) Hence, since A = B = D = 0, and at x = 0, sin λ x = 0, cos λ x = 1, and e−λ x = 1. 7). Let the boundary conditions at the top or the mudline be expressed as follows: 1. M = Mt at x = 0, which implies that (d2v/dx2) = Mt at x = 0. 2. Pt = 0 at x = 0, which implies that EI (d3v/dx3) = 0 at x = 0. 14c gives 2EI l 3 e − lx (D + C ) = 0 Therefore, D = −C. 7 Pile with moment at top. 14a gives 2 EI λ2 (−D) = Mt. Therefore, D = Mt/(2 EI λ2) and C = −Mt/(2 EI λ2). 8 shows a schematic of the above condition, that is, pile ixed at the top.

7 Pile with moment at top. 14a gives 2 EI λ2 (−D) = Mt. Therefore, D = Mt/(2 EI λ2) and C = −Mt/(2 EI λ2). 8 shows a schematic of the above condition, that is, pile ixed at the top. For this case, the boundary conditions at the top are given by the following equations: 1. dv/dx = 0 at x = 0 2. 8 Pile ixed against rotation at top. 1 shows values of various parameters for the analytical solution for 1-D laterally loaded pile. 048 m) from the top. Find (a) the maximum (positive) moment, Mmax, and (b) the maximum delection, vmax.

34 Advanced Geotechnical Engineering The solutions for vM, vM+2, and vM+2 can be obtained by following a similar procedure as for load at the top of the pile. 46b, respectively. 53) Similarly, equations can be derived for other loading cases such as moment at the top, and so on, and the procedures can also be used to address other types of boundary conditions. The solution procedures can be used with hand calculations, and also computerized. 29) can be used to develop a general computer procedure resulting in a set of simultaneous equations, which can be solved for displacements at all nodes (m = 0 to M) for various boundary conditions.

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